B\u00f3ng l\u00f4 \u0111\u1ec1 trong ng\u0169 h\u00e0nh quy \u0111\u1ecbnh: <\/li>\n<\/ul>\n\n\n\n-Th\u1ee7y t\u01b0\u01a1ng \u1ee9ng v\u1edbi s\u1ed1 1. <\/p>\n\n\n\n
-Kim t\u01b0\u01a1ng \u1ee9ng v\u1edbi s\u1ed1 2. <\/p>\n\n\n\n
-H\u1ecfa t\u01b0\u01a1ng \u1ee9ng v\u1edbi s\u1ed1 3. <\/p>\n\n\n\n
-Th\u1ed5 t\u01b0\u01a1ng \u1ee9ng v\u1edbi s\u1ed1 4. <\/p>\n\n\n\n
-M\u1ed9c t\u01b0\u01a1ng \u1ee9ng v\u1edbi s\u1ed1 5. <\/p>\n\n\n\n
Trong \u0111\u00f3, quan h\u1ec7 t\u01b0\u01a1ng sinh trong ng\u0169 h\u00e0nh l\u00e0: M\u1ed9c sinh H\u1ecfa – H\u1ecfa sinh Th\u1ed5 – Th\u1ed5 sinh Kim – Kim sinh Th\u1ee7y – Th\u1ee7y Sinh M\u1ed9c. <\/p>\n\n\n\n
Th\u1ee9 t\u1ef1 t\u01b0\u01a1ng kh\u1eafc l\u00e0: Th\u1ee7y kh\u1eafc H\u1ecfa – H\u1ecfa kh\u1eafc Kim – Kim kh\u1eafc M\u1ed9c – M\u1ed9c kh\u1eafc Th\u1ed5 – Th\u1ed5 Kh\u1eafc Th\u1ee7y. <\/p>\n\n\n\n
T\u1eeb \u0111\u00f3, ta suy ra \u0111\u01b0\u1ee3c nh\u1eefng con s\u1ed1 lu\u1eadn theo quy lu\u1eadt b\u00f3ng ng\u0169 h\u00e0nh nh\u01b0 sau: <\/p>\n\n\n\n
-B\u00f3ng d\u01b0\u01a1ng ng\u0169 h\u00e0nh bao g\u1ed3m: 1-6, 2-7, 3-8, 4-9, 5-0.<\/p>\n\n\n\n
-B\u00f3ng \u00e2m ng\u0169 h\u00e0nh bao g\u1ed3m: 1-4, 2-9, 3-6, 5-8, 0-7. <\/p>\n\n\n\n
V\u00ed d\u1ee5: Soi s\u1ed1 \u0111\u1ec1 ch\u1eafc \u0103n 100 %<\/strong> theo b\u00f3ng trong l\u00f4 \u0111\u1ec1 ng\u0169 h\u00e0nh th\u00ec 47 th\u00ec t\u01b0\u01a1ng \u1ee9ng v\u1edbi h\u1ec7 Th\u1ed5 Kim. Ta c\u00f3 Th\u1ed5 r\u1ed3i \u0111\u1ebfn Kim (4 s\u1ebd th\u00e0nh 2), Kim r\u1ed3i \u0111\u1ebfn M\u1ed9c (7 s\u1ebd th\u00e0nh 0, lu\u1eadn theo b\u00f3ng d\u01b0\u01a1ng ng\u0169 h\u00e0nh). <\/p>\n\n\n\n=> Ta thu \u0111\u01b0\u1ee3c 47 = Th\u1ed5 Kim = Kim M\u1ed9c = 20. S\u1eed d\u1ee5ng con 20 \u0111\u1ec3 \u0111\u00e1nh trong ng\u00e0y. <\/p>\n\n\n\n